25x^2+131x+105=0

Solution for 25x^2+131x+105=0 equation:

25x^2+131x+105=0

a = 25; b = 131; c = +105;
Δ = b2-4ac
Δ = 1312-4·25·105
Δ = 6661
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(131)-\sqrt{6661}}{2*25}=\frac{-131-\sqrt{6661}}{50}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(131)+\sqrt{6661}}{2*25}=\frac{-131+\sqrt{6661}}{50}
$